Ventilation Management
It is very important to study the Effective Temperature, which is the actual temperature perceived by the bird and is influenced by the interaction between:
1- Ambient temperature
2- Humidity
3- Air speed
Heat Stress Number
There is a strong relationship between dry air temperature and relative humidity (the amount of water vapor in the air). Their combined value produces heat stress on the bird and is expressed as:
Heat Stress Number = Temperature (°F) + Relative Humidity (%)
Temperature Conversion:
To convert Celsius to Fahrenheit:
°F = (°C × 9/5) + 32
To convert Fahrenheit to Celsius:
°C = (°F − 32) × 5/9
Heat Stress Interpretation:
If the sum < 150 → No problem
If it reaches 155 → Beginning of stress
If it reaches 160 → Feed intake stops, water intake increases, production decreases
If it reaches 165 → Mortality begins
If it reaches 170 → Severe mortality (real catastrophe)
Heat Transfer Methods
Heat transfer from any body occurs through three methods:
Radiation — Convection — Conduction
Birds radiate heat from their bodies sufficient to warm themselves in cold environments.
A bird weighing 1 kg radiates 5.5–6.5 kcal/hour.
Thus, a 21‑day‑old bird weighing 1 kg can maintain warmth without air drafts.
Factors Affecting House Ventilation
1- Outside temperature
2- Wind speed
3- Thermal conductivity
4- Air exchange rate inside the house
5- Atmospheric pressure
6- Heat radiation from birds
Negative Effects of Ammonia
Ammonia has harmful effects on birds, causing:
Reduced daily weight gain — Skin irritation — Breast burns — Eye inflammation — Footpad burns — Increased heart rate — Poor flock uniformity
Effect of Ammonia Levels on Feed Intake and Weight
Ammonia concentration — Feed consumption — Body weight
0 ppm → 2.19 kg — 1.56 kg
25 ppm → 2.14 kg — 1.44 kg
50 ppm → 1.86 kg — 1.16 kg
Thus, increasing ammonia levels reduces feed intake and body weight.
Required Air Quality Levels
1- Recommended ammonia level ≤ 10 ppm
2- Detectable by humans at 5 ppm
3- At 20 ppm → Affects respiratory cilia
4- At 25–50 ppm → Reduced body weight and feed conversion
Ventilation
Ventilation stages according to environmental conditions:
1- Minimum Ventilation
2- Transitional Ventilation
3- Tunnel Ventilation
Minimum Ventilation System
Used during cold weather and brooding periods.
Used to change air without lowering house temperature.
Operates using a timer.
Used only in the early days of bird age.
Prevents moisture buildup, ammonia, and CO₂ accumulation.
Air speed ≤ 0.2 m/s
Air exchange once every 5 minutes
Purposes:
Providing oxygen — Controlling humidity — Maintaining litter quality
This system depends on negative pressure.
Negative Pressure
Negative pressure means exhausting air from inside the house so fresh air enters through inlets, creating a partial vacuum.

Pressure should not exceed 25 Pascals.
Transitional Ventilation
Used when house temperature exceeds outside temperature.
Air speed ≈ 0.5 m/s
Air exchange once every 2 minutes

Used from day 10 to day 28
Tunnel Ventilation
Used in hot weather to reduce house temperature.
Air speed 1.7–2.5 m/s
Air exchange once per minute
May use evaporative cooling pads
Not used before 28 days of age
House Volume Calculation

House volume = Length × Width × Average height
Example:
100 × 14 × 2.7 = 3780 m³
Minimum ventilation airflow:
3780 ÷ 5 = 756 m³/min
Fan capacity example:
42,500 m³/hour = 708 m³/min
Number of fans:
756 ÷ 708 ≈ 1 fan
Tunnel ventilation calculation:
Cross‑sectional area:
13.8 × 2.7 = 37.26 m²
Required airflow:
37.26 × 2.5 = 93.15 m³/s
Fan capacity:
11.8 m³/s
Number of fans:
93.15 ÷ 11.8 ≈ 8 fans
Cooling Pad Area Calculation
Pad area depends on airflow and pad thickness.
To calculate the cooling pad area, the following must be known:
Air volume = Cross-sectional area × Air velocity
= 37.26 × 2.5
= 93.15 m³/s
Required pad area = Air volume ÷ Air velocity through pads
= 93.15 ÷ 2
= 46.75 m²
Assuming pad height = 1.5 m
Pad length = 46.75 ÷ 1.5
= 31.2 m
If installed on two sides:
Length per side = 31.2 ÷ 2
= 15.6 m per side
Air velocity = 1.25 m/s
Pad area = 93.15 ÷ 1.25
= 74.5 m²
With pad height 1.5 m:
Pad length = 74.5 ÷ 1.5
= ≈ 50 m
On two sides:
Length per side = 50 ÷ 2
= 25 m per side
Prepared by:
Eng. Nader Saeed El‑Hadary